[Python] 纯文本查看 复制代码 import re
val = """
<li><a href="/kegg-bin/show_pathway?14245484684/hsa01100.args" target="_blank">hsa01100</a>
Met**lic pathways - Homo sapiens (<a href="javascript:display('hsa0118')">58</a>)
<li>
"""
ret = re.findall("href=\"(.*?)\" target.*?</a>([\s\S]*?)\(<a.*?display\('(.*?)'\)\">(\d+)<", val)
print(ret)
# [('/kegg-bin/show_pathway?14245484684/hsa01100.args', ' \nMet**lic pathways - Homo sapiens ', 'hsa0118', '58')] |